How much heat is required to take a 150 g sample of water from 10.0 ℃ to 95.0 ℃? cs, water = 4.184 J/g*℃

Explanation:

We are given the specific heat and change in temperature, so we should use this heat formula:

where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

We know the mass is 150 grams. The specific heat of water is 4.184 J/g °C.

Let's find the change in temperature.

Subtract the initial temperature from the final temperature.

Now we know all the values:

Substitute them into the formula.

Multiply all three numbers together. Note that the grams (g) and degrees Celsius (°C) will cancel out. Joules (J) will be the only remaining unit.

53,346 Joules of heat are required.

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answer

fusion: the energy source of stars. the energy released from the collapse of the gas into a protostar causes the center of the protostar to become extremely hot. when the core is hot enough, nuclear fusion commences. fusion is the process where two hydrogen atoms combine to form a helium atom, releasing energy.

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