calculate the mass of barium nitride that is needed to produce a 2mol/L solution with a volume of 500ml

Mass = 261.34 g

Explanation:

Given data:

Mass of barium nitride = ?

Molarity of solution = 2 M

Volume of solution = 500 mL

Solution;

Volume of solution = 500 mL× 1L /1000 mL

Volume of solution = 0.5 L

Number of moles of of barium nitride:

Molarity = number of moles / volume in L

2 M = number of moles /0.5 L

Number of moles = 2 M × 0.5 L

Number of moles = 1 mol

Mass of barium nitride:

Mass = number of moles ×  molar mass

Mass = 1 mol × 261.34 g/mol

Mass = 261.34 g

i believe the answer is a.