How many moles of carbon dioxide are produced when 12.1 g of HF are reacted with an excess amount of sodium carbonate? Na2CO3 (aq) + 2 HF (aq) → H2O (ℓ) + CO2 (g) + 2 NaF (aq)

0.3025 moles of CO₂  are produced

Explanation:

Reaction is: Na₂CO₃ (aq) + 2 HF (aq) → H₂O (l) + CO₂ (g) + 2 NaF (aq)

It is correctly ballanced.

If the given information stays that the excess amount is on the sodium carbonate, the HF is the limiting reagent.

We see that stoichiometry is 2:1. Moles of produced CO2, will be the half, than the original amount, we have.

Firste step: We convert the mass to moles

12.1 g . 1mol / 20g = 0.605 moles of HF

2 moles of HF can produce 1 mol of CO₂

0.605 moles of HF will produce (0.605 . 1) /2 = 0.3025 moles of CO₂

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explanation:

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.