6CO2  + 6H2O  —>  C6H12O6  +  6O2   
If 12 moles of oxygen were produced, how many moles of carbon dioxide were used? 

12 number of moles of carbon dioxide are used.

Explanation:

Given data:

Number of moles of oxygen produced = 12 mol

Number of moles of CO₂ used = ?

Solution:

Chemical equation:

6CO₂ + 6H₂O      →     C₆H₁₂O₆ + 6O₂

Now we will compare the moles of oxygen with carbon dioxide.

                     O₂            :          CO₂

                      6             :             6

                    12              :             12

Thus, 12 number of moles of carbon dioxide are used.

hloride, what is the mass of calcium in

explanation:

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole