Describe the preparation
of 2.00h of o.108m Bach
from Bad. 28 (244-3 g/mal)

The question is incomplete, the complete question is; Describe the preparation of 2.00 L of 0.108 M BaCl2 from BaCl2.2H2O

See explanation

Explanation:

First we must know the molar mass of the compound = 244.3 g/mol

Now we must calculate the number of moles of BaCl2.2H2O in the solution.

number of moles = concentration * volume = 0.108 M * 2.00 L = 0.216 moles

Now the mass of solid that we need to take can be obtained from;

number of moles = mass/molar mass

mass = number of moles * molar mass

mass = 0.216 moles * 244.3 g/mol

Mass = 52.8 g

Hence, we must weigh 52.8 g of BaCl2.2H2O accurately in a balance and dissolve it in 2 L of water to give 0.108 M solution of BaCl2.2H2O.

the link still does not work even when adding it to the url bar

explanation:

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