a solution of AICI is combined with a solution of KOH. Identify the precipitate and the spectator ions in the resulting reactions.

The  the precipitate : Al(OH)₃(s)

The spectator ions : 3Cl⁻ and 3K⁺

Reaction

AlCl₃ + 3KOH → Al(OH)₃ + 3KCl

From solubility rules :

Compounds of OH− are insoluble except Compounds of Li +, Na +, K +, Rb +, Cs +, NH₄⁺ , Sr²⁺, and Ba²⁺

Compounds of Cl−, Br−, I− are soluble except Ag⁺, Hg₂²⁺, Pb²⁺

So the  the precipitate : Al(OH)₃(s)

net ionic reaction

AlCl₃ + 3KOH → Al(OH)₃ + 3KCl

Al³⁻+3Cl⁻+3K⁺+3OH⁻⇒Al(OH)₃(s)+3K⁺+3Cl⁻

Remove the spectator : 3Cl⁻ and 3K⁺

Al³⁻(aq)+3OH⁻(aq)⇒Al(OH)₃(s)

lol for the pointsss

i think that the answer is c