Chemistry, 02.02.2020 07:43 dbn4everloved8

4na+o2-> 2na2o how many grams of na2o are produced when 95.7g of na reacts?

Answers: 3

Show answers

Another question on Chemistry

Chemistry, 22.06.2019 21:30

Athe top of a hill, an athlete on a skateboard has x joules of mechanical energy. how much mechanical energy will she have at the bottom of the hill? ignore the effects of friction.

Answers: 1

Answer

Chemistry, 23.06.2019 12:00

Asubstance that will change shape to fit its container but has a definite volume is in a phase of matter

Answers: 1

Answer

Chemistry, 23.06.2019 16:00

Instructions: the table below explains the average rate at which some geologic processes occur. calculate the amount of sea level change, erosion, and uplift for 100,000 years, 1,000,000 years, and 10,000,000 years. remember, 100 cm = 1 m. fill out the table completely and answer the below questions in complete sentences. for with completing the table, use this video: if you need directions on how to submit your assignment, click on the link due by sunday at midnight for full credit. if submitted late, you will receive a 30% grade deduction. check your pacing guide for assignment dates. process rate per 1,000 years after 100,000 years after 1,000,000 years after 10,000,000 years sea level changes 10 m 1000 10000 100000 regional erosion 2 m 200 2000 20000 uplift 10 cm 1. what is the fastest process, sea level changes, erosion, or uplift? 2. what is the slowest process, seal level changes, erosion, or uplift?

Answers: 3

Answer

Chemistry, 23.06.2019 16:00

Challenge question: this question is worth 6 points. as you saw in problem 9 we can have species bound to a central metal ion. these species are called ligands. in the past we have assumed all the d orbitals in some species are degenerate; however, they often are not. sometimes the ligands bound to a central metal cation can split the d orbitals. that is, some of the d orbitals will be at a lower energy state than others. ligands that have the ability to cause this splitting are called strong field ligands, cnâ’ is an example of these. if this splitting in the d orbitals is great enough electrons will fill low lying orbitals, pairing with other electrons in a given orbital, before filling higher energy orbitals. in question 7 we had fe2+, furthermore we found that there were a certain number (non-zero) of unpaired electrons. consider now fe(cn)6 4â’: here we also have fe2+, but in this case all the electrons are paired, yielding a diamagnetic species. how can you explain this?