Calcium carbonate is a white mineral. A chemist burns calcium carbonate, CaCO3, to produce carbon dioxide, CO2, and a white powder, CaO. The following chemical equation shows the reaction. CaCO3 > CO2 + CaO

A. Compare the properties of the products and reactants in this reaction.

B. Use numbers of atoms to describe the amounts of calcium, carbon, and oxygen before and after the reaction.

A chemist burns calcium carbonate, CaCO3, to produce carbon dioxide, CO2, and a white powder, CaO. The following chemical equation shows the reaction.

Explanation:

m carbonate, CaCO3, to produce carbon dioxide, CO2, and a white powder, CaO. The following chemical equation shows the reaction.

hviycxiuyxhmhgjgjb

B. Use numbers of atoms to describe the amounts of calcium, carbon, and oxygen before and after the reaction.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o