Determine the amount of sodium hypochlorite in Bleach you tolerated a 23.82 ml sample of 0.0100 M KIO cuboid with a solution of Na squared S squared O cubid of unknown concentration. The endpoint was observed to occur at 12.38 ml. How many moles of KIO cubid wewe titrated

The moles of KIO cuboid titrated are 0.0002382

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,

n = moles of solute

= volume of solution in ml

Now put all the given values in the formula of molarity, we get

Therefore, the moles of KIO cuboid are 0.0002382

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

it means there are 3 atoms of oxygen