Calculate the maximum volume in mL of 0.20 M HCl that a tablet containing 338 mg Al(OH)3 and 489 mg Mg(OH)2 would be expected to neutralize. Assume complete neutralization.

148.85 mL

Explanation:

The reactions that take place are:

Now we calculate how many HCl moles would react with 338 mg of Al(OH)₃. First we convert Al(OH)₃ mg into mmol, using its molar mass:

Then we convert mmol Al(OH)₃ into mmol HCl:

Now we do the same calculations for Mg(OH)₂, using its molar mass:

And convert into mmol HCl:

Now we add the reacting mmoles of HCl together

Finally we calculate the volume of a 0.20 M solution that contains 29.77 mmoles of HCl:

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.