The compound sodium iodide is a strong electrolyte. Write the reaction when solid sodium iodide is put into water.

NaI(s) → Na⁺(aq) + I⁻(aq)

Explanation:

The chemical formula of sodium iodide is NaI. When NaI is dissolved in water, it dissociates into sodium ions (Na⁺) and iodide ions (I⁻). One mol of NaI gives 1 mol of Na⁺ ions and 1 mol of I⁻ ions.

Therefore, the chemical equation for the dissociation is the following:

NaI(s) → Na⁺(aq) + I⁻(aq)

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explanation:

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6