What's the balanced equation for Iron and copper (II) sulfate solution.

 2Fe +  3CuSO₄  →  Fe₂(SO₄)₃   +  3Cu

Explanation:

The reactants are:

   Iron  = Fe

  Copper (II) sulfate solution = CuSO₄

The reaction is given as:

            Fe +  CuSO₄  →  Fe₂(SO₄)₃   +  Cu

This is a single displacement reaction;

  Now let us balance the equation;

             aFe +  bCuSO₄  →  cFe₂(SO₄)₃   +  dCu

Conserving Fe;

                       a  = 2c

  Conserving  Cu;

                      b  = d

  Conserving S;

                      b  = 3c

  Conserving O;

                    4b  = 12c  

let b  = 1;

    c =  

     d  = 1

     a  =

Multiply through by 3 to get whole numbers;

  a  = 2, b = 3, c  = 1 and d  = 3

           2Fe +  3CuSO₄  →  Fe₂(SO₄)₃   +  3Cu

b.final

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.