Help Please All substances taking part in a certain interaction are shown below: (5 points)

Calcium Carbonate is written after that an equal to sign is shown followed by Calcium Oxide followed by an addition sign followed by Carbon dioxide. Just below Calcium Oxide 112 grams is written and just below Carbon dioxide 88 grams is written

Which of the following is the correct estimate of the amount of calcium carbonate used in the interaction?
Sum of 112 g and 88 g
Difference between 112 g and 88 g
Twice the sum of 112 g and 88 g
Twice the difference between 112 g and 88 g

Hey there!

The correct answer is "sum of 112+88 g"...

The calcium carbonate has 88g in a fine manor which goes along with 1128.

Hope this helps! Happy Holidays and stay safe!

Explanation:

i think it's letter a.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole