In a second-order reaction (one that is second order in one reactant), cutting in half the concentration of that reactant will have what effect on the reaction rate?

a) the reaction rate will remain the same.
b) the reaction rate will double.
c) the reaction rate will decrease by a factor of two.
d) the reaction rate will increase by a factor of four.
e) the reaction rate will decrease by a factor of four.

D) The reaction rate will increase by a factor of four.

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

given order =2 , thus rate law is:

     (1)

On cutting the concentration of  A to half

     (2)

Dividing 2 by 1  

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

you did not give any options thus this is the best answer i can give to you with this little information you have given

> they are both natural and not man made

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