Chemistry, 06.12.2020 05:20 zmeister

2 Aluminum oxidizes according to the following equation: 4A1 + 302 → 2Al2O, [a] Powdered Al (0.048 myl) is placed into a container containing 0.030 mol O.. What is the limiting reactant?

[b] How many moles of the excess reoctant remaine?

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2 Aluminum oxidizes according to the following equation: 4A1 + 302 → 2Al2O, [a] Powdered Al (0.048...

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2 Aluminum oxidizes according to the following equation: 4A1 + 302 → 2Al2O, [a] Powdered Al (0.048 myl) is placed into a container containing 0.030 mol O.. What is the limiting reactant?[b] How many moles of the excess reoctant remaine?

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Another question on Chemistry

2 Aluminum oxidizes according to the following equation: 4A1 + 302 → 2Al2O, [a] Powdered Al (0.048 myl) is placed into a container containing 0.030 mol O.. What is the limiting reactant?

[b] How many moles of the excess reoctant remaine?