If a given solution contains 3.55 mol of calcium hydroxide, and the solution as a molarity of 0.667 M, what is the volume of the solution?

Volume in L = 5.3 L

Explanation:

Given data:

Number of moles of calcium hydroxide = 3.55 mol

Molarity of solution = 0.667 M

Volume of solution = ?

Solution:

Formula:

Molarity = number of moles / volume in L

By putting values,

0.667 M = 3.55 mol / volume in L

Volume in L = 3.55 mol / 0.667 M

Volume in L = 5.3 L

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.