What is the oxidation number of tin (sn) in the compound na2sno2? a. -2 b. 0 c. +2 d. +3

O.N. of Na = +1

O.N. of O = -2

Let, O.N. of Tin = x

1*2 + x + -2*2 = 0

2+x-4 = 0

x-2 = 0

x = 2

SO OPTION C IS YOUR ANSWER

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