A chemist has to prepare 750.0 mL of a 0.200 M KNO3(aq) solution. What mass, in grams, of potassium nitrate (formula mass 101.11 g/mol) would they use

They would use 15.17 g KNO₃.

Explanation:

To solve this problem first we calculate the number of KNO₃ moles that would be in the solution, multiplying the concentration times the volume:

750 mL ⇒ 750 / 1000 = 0.750 L

Then we convert moles of KNO₃ to grams, using its molar mass:

po-215 i got it right on the quiz

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error