Which reactant will be used up first if 78.1g of o2 is reacted with 62.4g of c4h10? A. c4h10
B. o2
C. co2
D. h2o

Reagent O₂ will be consumed first.

Explanation:

The balanced reaction between O₂ and C₄H₁₀ is:

2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

Then, by reaction stoichiometry, the following amounts of reactants and products participate in the reaction:

Being:

The molar mass of the compounds that participate in the reaction is:

Then, by reaction stoichiometry, the following mass quantities of reactants and products participate in the reaction:

If 78.1 g of O₂ react, it is possible to apply the following rule of three: if by stoichiometry 416 g of O₂ react with 116 g of C₄H₁₀, 62.4 g of C₄H₁₀ with how much mass of O₂ do they react?

mass of O₂= 223.78 grams

But 21.78 grams of O₂ are not available, 78.1 grams are available. Since you have less mass than you need to react with 62.4 g of C₄H₁₀, reagent O₂ will be consumed first.

it's all four options.

i believe the answer is three water molecules