In the case of a rigid rorator, i. e. two masses M1 and M2 placed on a rigid weightless rod, we start from the Schrodinger equation for two particles 1 and 2, and then we separate the movement of the center of masses. Give the formulas of both masses that we get as part of this procedure. Calculate these masses in atomic mass units for the HD molecule by approximating the masses H and D with their mass numbers.

Masses in atomic mass units for the HD molecule by approximating the masses H and D with their mass numbers is explained below in complete detail.

Explanation:

Two volumes M1 and M2 are located on a rigid weightless rod in a rigid rotor position. Energy in a rigid rotator example: E = BJ(J+1) where, B = h/8pi2Ic, B is rotational regular, I is moment of inertia = ur2 where u is decreased mass = m1m2/m1+m2.

FOR HD MOLECULE: mass, u = mass of H*mass of D/mass of H + D. Atomic mass unit =1.67*10^-27 kg. So, u = 1*1.67*10-24 * 2*1.67*10-24 / 1.67*10-24+2*1.67*10-24 = 1.67*10-24*2/3 = 1.11*10-24 g.

i will, dm me on here.

explanation:

i need some with some bio stuff see if anyone will

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.