A 30 gram ball is at rest. Next, a force pushes the ball to the north for 2.5 seconds and the ball accelerates for a rate of 0,70 m/s/s. How fast is the ball going after the 2.5 seconds of acceleration? For credit, who work in detail

1.75m/s or 6.3km/hr

Explanation:

here,

acceleration (a) = 0.7m/s^2

mass (m) = 30g

time (t) = 2.5s

initial velocity (u) = 0m/s

final velocity (v) = ?

now,

v = u + at

or, v = 0 + 0.7 * 2.5

hence, Final velocity (v) = 1.75 m/s

if u want to convert to km/hr

then,

1.75 * 3.6 (we know that 1m/s = 3.6km/hr)

= 6.3km/hr

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).

the answers would be

the first one and the second one