Explain how the rate of diffusion of a gas is related to its molar mass. Carbon dioxide gas (CO2) effuses 3.2 times faster than an unknown gas. Determine the molar mass of the unknown gas

450.24

Explanation:

According to Graham's law of diffusion:

R1/R2 = √M.M2 / √ M.M1

where

R1 = rate if diffusion of the first gas

R2 = rate of diffusion of the second gas

M.M2 = molar mass of the second gas

M.M1 = molar mass of the first gas

The first gas is CO2 and CO2 has a molar mass of 44

R1/R2 = 3.2

Substitute all the values into the equation:

3.2 = √M.M2 / √44

Squaring both sides:

3.2^2 = M.M2 / 44

Cross multiply as follows:

M.M2 = 3.2*3.2*44

= 450.56

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )