Chemistry, 01.12.2020 20:40 brooklyn674

Select the set of quantum numbers that is not permitted. n = 2, l = 1, ml = 1, ms = +½

n = 1, l = 0, ml = 0, ms = –½

n = 4, l = 3, ml = 3, ms = –½

n = 3, l = 3, ml = 2, ms = +½

n = 3, l = 0, ml = 1, ms = +½

Answers: 3

Show answers

Answers

Answer from: Quest

No is the answer to the question

Answer from: Quest

pv=nrt

explanation:

Answer from: Quest

the missing options are :

(1) lower boiling point and a lower freezing point(2) lower boiling point and a higher freezing point(3) higher boiling point and a lower freezing point(4) higher boiling point and a higher freezing point

answer : the correct answer is option (3) higher boiling point and a lower freezing point

explanation :

when a non volatile solute is added to a solvent like water, it results in elevation of boiling point.

let us find the increase in boiling point of water when cacl₂ is added to water to make a solution of 1 m

step 1 : find molality of the solution

let us assume we have 1 l of solution.

$m = \frac{moles (solute)}{l ( solution)}$

$1 m = \frac{moles (cacl_{2})}{1 l }= 1 mol cacl_{2}$

let us convert this to grams of cacl₂.

molar mass of cacl2 is 111 g/mol

grams of cacl₂ = $1 mol \times \frac{111g}{mol} = 111 g cacl_{2}$

mass of solute = 111 g

assuming density of solution same as water which is 1g/ml we have ,

mass of solution = density * volume

mass of solution = $\frac{1g}{ml} \times 1000 ml = 1000 g$

mass of solution = mass of solvent + mass of solute

mass of solute = 1000g - 111g

mass of solute 889 g = 0.889 kg

the molality of the solution can be calculated as

$molality = \frac{mol (solute)}{kg ( solvent)}$

$molality = \frac{1mol}{0.889kg}$

molality = 1.12 m

step 2 : find boiling point elevation.

the elevation in boiling point is calculated as

$\bigtriangleup t_{b} = i \times k_{b} \times m$

here δtb = boiling point elevation

i = vant hoff factor which is the number of ions formed by the solute .

cacl₂ dissociates as $cacl_{2} \rightarrow ca^{2+} + 2 cl^{-}$

it forms 3 ions . therefore,

i = 3

m = molality which is 1.12 m

kb is constant for a given solvent. for water it is 0.512

$\bigtriangleup t_{b} = 3 \times 0.512 \times 1.12$

$\bigtriangleup t_{b} = 1.7$

the boiling point of water increases by 1.7 °c

step 3: find freezing point depression.

when a non volatile solute is added to water, it results in decrease in freezing point.

the formula to find freezing point depression is

$\bigtriangleup t_{f} = i \times k_{f} \times m$

kf is constant for water and its value is 1.86

$\bigtriangleup t_{f} = 3 \times 1.86 \times 1.12$

$\bigtriangleup t_{f} = 6.2$

the freezing point of water decreases by 6.2 °c

therefore we can say that, the solution will have a higher boiling point and a lower freezing point

Answer from: Quest

A-rna has coded instructions for making proteins, and dna translates the code.

Another question on Chemistry

Chemistry, 22.06.2019 08:30

Which of the following would be an accurate picture of the earth during the summer time of the northern hemisphere?

Answers: 1

Answer

Chemistry, 23.06.2019 00:30

Five different substances are given to you to be dissolved in water. which substances are most likely to undergo dissolution in water? check all that apply. view available hint(s) check all that apply. sodium fluoride, naf octane, c8h18 propanol, ch3ch2ch2oh potassium iodide, ki benzene, c6h6

Answers: 1

Answer

Chemistry, 23.06.2019 11:00

Achemist weighed out 101.g of silver. calculate the number of moles of silver she weighed out.

Answers: 2

Answer

Chemistry, 23.06.2019 12:10

Which structure is a valid representation of a hydrocarbon molecule?

Answers: 2

Answer

You know the right answer?

Select the set of quantum numbers that is not permitted. n = 2, l = 1, ml = 1, ms = +½

...