What is the pressure in atmospheres exerted by a column of water that is 12.5 m high?
(density of water = 1.00g/cm3; gravitational constant = 9.80665 m/s2, 1 atm =
101,325 Pa = 760 torr = 760 mmHg)

0.00121 atm

Explanation:

Step 1: Given data

Step 2: Calculate the pressure exerted by the column of water in SI units

The pressure exerted by the column of liquid depends on the height of the column, the density of the liquid and the gravitational constant. We can calculate it using the following expression.

P = ρ × g × h

P = 1.00g/cm³ × 9.80665 m/s² × 12.5 m

P = 123 Pa

Step 3: Convert "P" to atm

We will use the conversion factor 101325 Pa = 1 atm.

123 Pa × (1 atm/101325 Pa) = 0.00121 atm