Iron reacts with oxygen to produce iron oxide (rust). this reaction is represented in an equation as 4fe + xo2 → 2fe2o3. identify the value of x that will balance the equation.
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Answer is:  the value of x is 3.

Chemical reaction: Fe + O₂ → Fe₂O₃.

Oxidation half reaction: Fe⁰ → Fe⁺³ + 3e⁻ /×4; 4Fe⁰ → 4Fe⁺³ + 12e⁻.

Reduction half reaction: O₂⁰+ 4e⁻ → 2O⁻²/×3; 3O₂⁰+ 12e⁻ → 6O⁻².

Balanced chemical reaction: 4Fe + 3O₂ → 2Fe₂O₃.

Oxidation is increase of oxidation number, iron is oxidized from oxidation number 0 (Fe) to oxidation number +3 (in rust Fe₂O₃).

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;