A gas with a pressure of 820.4 mmHg occupies a volume of 900.0 mL at a temperature of 25.0°C. If
the pressure does not change, what is the new
volume of the gas at 132.0°C?
A) 1220 L
B) 4750 L
C) 4750 mL
D) 1220 mL

V₂ = 1223.2 mL  

Explanation:

Given data:

Pressure of gas = 820.4 mmHg

Initial volume of gas = 900.0 mL

Initial temperature = 25.0°C (25+273=298K)

Final temperature = 132.0°C (132.0 +273 = 405 K)

Final volume = ?

Solution:

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 900.0 mL × 405 K / 298 k

V₂ = 364500 mL.K / 298 K

V₂ = 1223.2 mL  

a corroding iron, if that's one of your choices

c) should be the answer.