Using the following thermochemical equation, calculate how much heat is associated with the decomposition of 4.00 moles of NH4Cl. NH3(g) + HCl(g) è NH4Cl(s) ΔH = -176 kJ

A) 5000
B) 740
C) 407
D) 704

D - 704

Explanation:

The balanced thermochemical equation relates the energy change to moles, not grams, so we first convert the amount of NH4Ck to moles and then use the thermochemical equation to determine the energy change:

4.00 mole NH4Cl x (-176 ÷ 1 mole NH4Cl)

= -704

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.