SECTION A For these questions, your equation will be straight forward to balance.

In a titration, 20 cm3 of 2.0 mol dm-3 HCl reacted with 25 cm3 of NaOH. What was the concentration of the sodium hydroxide?

In a titration, 20 cm3 of 0.2 mol dm-3 HCl reacted with 50 cm3 of NaOH. What was the concentration of the sodium hydroxide?

In a titration, 20 cm3 of 0.15 mol dm-3 HCl reacted with 25 cm3 of NaOH. What was the concentration of the sodium hydroxide?

In a titration, 20 cm3 of 1.14 mol dm-3 HCl reacted with 25 cm3 of NaOH. What was the concentration of the sodium hydroxide?

20cm=the length of the causation that it loads about the contrasting of the solution it is an easy question to answer it just has too many parts I answered one and I hope it helped to give you a hint towards solving the whole thing good luck

Explanation:

I tried!

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.