A competitive high school swimmer takes 56.7 seconds to swim 100. yards. What is his rate in m/min? m

min

96.72 m/min

Explanation:

The following data were obtained from the question:

Time (t) = 56.7 s

Distance (d) = 100 yard

Rate (R) =?

Next, we shall convert 56.7 s to minutes. This can be obtained as follow:

60 s = 1 min

Therefore,

56.7 s = 56.7 s × 1 min /60 s

56.7 s = 0.945 min

Next, we shall convert 100 yard to metre (m). This can be obtained as follow:

1 yard = 0.914 m

Therefore,

100 yard = 100 yard × 0.914 m /1 yard

100 yard = 91.4 m

Finally, we shall determine the rate of the swimmer as follow:

Time (t) = 0.945 min

Distance (d) = 91.4 m

Rate (R) =?

R = d/t

R = 91.4/0.945

R = 96.72 m/min

Thus the rate of the swimmer is 96.72 m/min

what does the table look like

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.