When 10 Joules of heat are transferred into 30 g of Copper at 18.20oC, the final temperature is 19.07oC. What is the specific heat of copper?

c = 0.38 j/g.°C

Explanation:

Given data:

Heat absorbed by copper = 10 j

Mass of copper = 30 g

Initial temperature = 18.20°C

Final temperature = 19.07°C

Specific heat capacity of copper = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 19.07°C -18.20°C

ΔT = 0.87 °C

10 J = 30 g×c×0.87 °C

10 J = 26.1 g.°C×c

c = 10 J /26.1 g.°C

c = 0.38 j/g.°C

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