Chemistry, 27.11.2020 22:40 Reijected

According to Coulomb’s law, what will happen to the electric force between two identical negative charges as they move closer together?

A. Fe will become negative and decrease in magnitude.

O B. Fe will stay negative and increase in magnitude.

C. Fe will stay positive and increase in magnitude,

D. Fe will become positive and decrease in magnitude.

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Answer from: neverender098

C. Fe will stay positive and increase in magnitude.

Explanation:

Coulomb's law states that the force of attraction of repulsion between two charged particles is directly proportional to the magnitude of their charges and inversely proportional to the square of the distance of separation between them.

This means that if the size of the charges are large, the force acting on them will be large as well. Also if the distance between the two charges increases the force decreases. However, the force increases when the distance of separation decreases.

Like charges repel, therefore, two negative charges brought together will repel each other, and the distance between the two charges decreases, the force will increase in magnitude. Forces of repulsion are considered positive, therefore, the force, Fe, will stay positive and increase in magnitude.

Answer from: Quest

i believe it is a.) released into

explanation:

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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