Calculate the volume of one mole of a gas at 1.00 atm pressure and 0 °C.

Solution:-

The gas is in the standard temperature and pressure condition i.e. at S.T.P

Therefore,

V

i

=22.4dm

3

V

f

=?

As given that the expansion is isothermal and reversible

∴ΔU=0

Now from first law of thermodynamics,

ΔU=q+w

∵ΔU=0

∴q=–w

Given that the heat is absorbed.

∴q=1000cal

⇒w=−q=−1000cal

Now,

Work done in a reversible isothermal expansion is given by-

w=−nRTln(

V

i

V

f

)

Given:-

T=0℃=273K

n=1 mol

∴1000=−nRTln(

V

i

V

f

)

⇒1000=−1×2.303×2×273×log(

22.4

V

f

)

Explanation:

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.