HELP!! GIVING 80 POINTS 4.95 g of ethylene (C2H4) are combusted with 3.25 g of oxygen.
(5 Points) Write a balanced equation. (ethylene plus oxygen yields carbon dioxide and water)

(5 Points) What is the limiting reactant? You must show your work.

(5 Points) If the actual yield of Carbon dioxide is 2.50 g, what is the percent yield for the reaction? You must show your work.

Liar its only 20 but ill take

Explanation:

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.