13. How many moles of sodium hydroxide are needed to neutralize 50grams of sulfuric acid? 2NaOH H2SO4 → Na2SO4 + 2H2O

1.02mole

Explanation:

The reaction equation is given as:

     2NaOH  +  H₂SO₄ →  Na₂SO₄  + 2H₂O

Given:

Mass of H₂SO₄  = 50g

Unknown:

Number of moles of NaOH = ?

Solution:

To solve this problem, we first find the number of moles of the acid given;

  Number of moles  =

Molar mass of H₂SO₄ = 2(1) + 32 + 4(16)  = 98g/mol

Now;

   Number of moles =   = 0.51mole

From the balanced reaction equation:

       1 mole of H₂SO₄ will be neutralized by 2 mole of NaOH

     0.51 mole of H₂SO₄ will be neutralized by 2 x 0.51  = 1.02mole of NaOH

chemistry sucks a**

explanation:

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.