Anyone know this ???

Hey There!_____________________________________

_____________________________________VESSEL A:

The superior vena cava (SVC) is the superior of the two venae cavae, It is located above inferior vena cava and it returns the deoxygenated blood from the systemic circulation to the right atrium of the heart.

----------------------------------------------------------------------VESSEL C:

The aorta is the main artery that carries blood away from your heart to the rest of your body.

----------------------------------------------------------------------ATRIUM D:

The Left Atrium is one of the two atriums, it receives the oxygenated blood from the lungs via Pulmonary vein.

----------------------------------------------------------------------VENTRICLE E:

The Left Ventricle is one of the two ventricles, it receives the oxygenated blood by the Left atrium through the mitral valves. From the ventricle oxygenated blood is provided to the whole body.

----------------------------------------------------------------------VESSEL B:

Pulmonary Artery is one of the two pulmonary vessels which connect the blood heart and lung. Pulmonary Artery takes the deoxygenated blood from the Right ventricle to the Lungs from the oxygenation.

_____________________________________Best Regards,'Borz'

All the elements are arranged by melting points on the periodic table. in row they go from metals to gasses. in the row from sodium to argon, sodium is more reactive than the one on its right, magnesium.

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.