You complete titration of 15.0ml of unknown acid with 14.16ml of 1.25 M NaOH. What’s the molar it’s of the unknown acid? Assume the acid is monoprotic 1 mole of acid reacts with 1 mole of base.

The molarity of the unknown acid : 1.18 M

Titration is a procedure for determining the concentration of a solution by reacting with another solution that is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range

Titration formula

M₁V₁n₁=M₂V₂n₂

monoprotic acid⇒n₁=1

NaOH monoprotic base⇒n₂=1

it is stable as it is in group 0 which have full outer shells of electrons

c. orbital shape i hope this is correct