A sample of neon gas occupies 5.5 liters at 20°C and 650 mmHg. What is the expected volume of the gas at S. T.P.

V₂ = 4.4 L

Explanation:

Given data:

Initial volume = 5.5 L

Initial pressure = 650 mmHg (650/760 =0.86 atm)

Initial temperature = 20 °C (20 +273 = 293 K)

Final temperature = 273 K

Final volume = ?

Final pressure =  1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

V₂ =  P₁V₁T₂/T₁ P₂

V₂ = 0.86 atm× 5.5 L × 273 K / 293 k × 1 atm

V₂ = 1291.29 atm.K.L / 293 k.atm

V₂ = 4.4 L