If I place a balloon in my fridge that initially has a pressure of 1.02 atm and a temperature of 11.2 °C, what will be the pressure (in atm) of the balloon when it is
fully cooled to 4.00°C by my refrigerator?

P₂ = 0.99 atm

Explanation:

Given data:

Initial pressure = 1.02 atm

Initial temperature = 11.2°C

Final pressure = ?

Final temperature = 4.00°C

Solution:

Initial temperature = 11.2°C (11.2+273 = 284.2 K)

Final temperature = 4.00°C (4.00+273 = 277 K)

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1.02 atm / 284.2 K = P₂/277 K

P₂ = 1.02 atm × 277 K / 284.2 K

P₂ = 282.54 atm. K /293 K

P₂ = 0.99 atm

catya your not at all which answer i've seen you do this on another question!