While performing a neutralization reaction, Jonna added 22.63 mL of 0.142 M H2SO4 to 46.21 mL of 0.304 M KOH. How many moles of OH- are unreacted in the solution after the neutralization is complete?

7.623 x 10⁻³ mol OH⁻

Explanation:

The reaction that takes place is:

Now we calculate how many moles of each reagent were added:

We calculate how many OH⁻ moles reacted with H₂SO₄:

Finally we substract the OH⁻ moles that reacted from the added ammount of OH⁻ moles:

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

indium, and thallium have three electrons i think