2. Find the ΔH for the reaction below, given the following reactions and subsequent ΔH values:

2C2(g) + H2O(g) → C2H2(g) + ⁵/₂ O2(g)

C2H2(g) + 2H2(g) → C2H6(g) ΔH = –94.5 kJ

H2O(g) → H2(g) + ½ O2 (g) ΔH =71.2 kJ

C2H6(g) + ⁷/₂ O2(g) → 2 CO2(g) + 3 H2O(g) ΔH = –283 kJ

hloride, what is the mass of calcium in

explanation:

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.