Given 8.55 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?

Grams of ethyl butyrate produced : 11.27 g

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

The reaction between Butanoic acid-C₄H₈O₂ and an excess Ethanol-C₂H₅OH to produce ethyl butyrate-C₆H₁₂O₂ :

C₄H₈O₂+C₂H₅OH⇒C₆H₁₂O₂+H₂O

mass Butanoic acid- C₄H₈O₂= 8.55 g, so mol C₄H₈O₂ (MW=88,11 g/mol) :

For 100% yield ⇒ actual=theoretical

Because Ethanol as an excess, so Butanoic acid as a limiting reactant and mol Ethyl butyrate based on mol Butanoic acid

From equation, mol ratio of mol C₆H₁₂O₂ : mol C₄H₈O₂ = 1 : 1, so : mol C₆H₁₂O₂=mol C₄H₈O₂= 0.097

mass C₆H₁₂O₂(MW=116.16 g/mol)

i think the answer is terrae but not 100 percent sure. ▓▬▬ §