Chemistry, 24.11.2020 02:40 brooklyn4682

Los rifles de juguete están compuestos de unos resortes. Si el proyectil de estos rifles es de 20,3g y el resorte se comprime 6,6cm. Halle la constante del resorte (aplicando la conservación de la energía) sí usted desea que el proyectil alcance una altura de 7,5m.

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Answer from: SissyBoo9680

$685.69\ \text{N/m}$

Explanation:

v = Velocidad final = 0

u = velocidad inicial

a = g = Aceleración debida a la gravedad = $9.81\ \text{m/s}^2$

s = Desplazamiento = 7.5 m

k = constante de resorte

x = Desplazamiento del resorte = 6.6 cm

Se supone que el rifle apunta hacia arriba.

De las ecuaciones de movimiento tenemos

$v^2-u^2=2as\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0-2\times -9.81\times 7.5}\\\Rightarrow u=12.13\ \text{m/s}$

a energía cinética del proyectil será igual a la energía potencial del resorte a medida que se conserva la energía.

$\dfrac{1}{2}mu^2=\dfrac{1}{2}kx^2\\\Rightarrow mu^2=kx^2\\\Rightarrow k=\dfrac{mu^2}{x^2}\\\Rightarrow k=\dfrac{0.0203\times 12.13^2}{0.066^2}\\\Rightarrow k=685.69\ \text{N/m}$

La constante de resorte es $685.69\ \text{N/m}$ .

Answer from: Quest

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.

Answer from: Quest

remember that hf is only the energy of one photon. not two. not three. one. 1) 5.12 * 10^3 photons find the energy of one photon, then determine how many photons are needed to reach the sensitivity. e = hf = (6.626 * 10^-34 js)(5.95 * 10^19 hz) = 3.94247 * 10^-14 j per photon (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons round to three sig figs. 2) 5.77 * 10^-17 j energy of pulse = energy per photon * number of photons = hfn = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250) = 5.774559 * 10^-17 j round to three sig figs. 3) 4.07 * 10^8 kj/mol 10^12 pm = 1 m c = fλ f = c/λ e = hf = hc/λ = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol) = 40702571.4 kj/mol round to three sig figs. 4) 9.94 * 10^-1 m e = hc/λ λ = hc / e = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j) = 0.9939 m round to three sig figs. 5) 9.06 * 10^3 photons energy of pulse = energy per photon * number of photons number of photons = energy of pulse / energy per photon = energy of pulse / (hf) = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)] = 9055.23695 photons round to three sig figs. 6) 2.78 * 10^-15 j this is problem 1, except in reverse. sensitivity = minumum number of photons * energy per photon = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz) = 2.78070758 × 10^-15 j round to three sig figs.

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Los rifles de juguete están compuestos de unos resortes. Si el proyectil de estos rifles es de 20,3g...

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