A sample of xenon occupies 1.90L at 251 kPa and -18°C. What was the temperature of the xenon if the gas originally measured 1.65 L at 205 kPa?

The temperature of the xenon : 180.863 K

Combined with Boyle's law and Gay Lussac's law  

P1 = initial gas pressure (N/m² or Pa)  

V1 = initial gas volume (m³)  

P2 = final gas pressure  

V2 = finalgas  volume  

T1 = initial gas temperature (K)  

T2 = final gas temperature  

P1=251 kPa

T1=-18+273=255 K

V1=1.9 L

P2=205 kPa

V2=1.65 L

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72