Consider the reaction between 75.5 mL of 0.247 M barium hydroxide and 95.0 mL of 0.330 M HCl. Find the mole ratio of hydrochloric acid to barium hydroxide, compare to the theoretical one, and determine the limiting reactant.

Explanation:

Ba( OH)₂ + 2HCl = BaCl₂ + 2H₂O .

75.5 mL of 0.247 M barium hydroxide = .0755  x .247 = .01864 moles

95.0 mL of 0.330 M HCl = .095 x .33 = .03135 moles

mole ratio of  hydrochloric acid to barium hydroxide

= .03135 /  .01864 = 1.68

theoretical ratio = 2 /1 = 2

As the theoretical ratio is more , therefore HCl is the limiting reactant  .

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2b2t

explanation:

2b2t