How many atoms are present in 9.8g of H2SO4

Explanation:

98 gH

2

SO

4

contains1 mole of H

2

SO

4

.

1 mole of H

2

SO

4

contain=1 mole of sulphur atoms.

∴9.8 g of H

2

SO

4

contain =0.1 mol of sulphur atom.

Thus, number of sulphur-atoms =n×N

A

(in 9.8 g of H

2

SO

4

)

=0.1×6.023×10

23

=0.6023×10

23

.

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