How much of glucose (C6H1206) is needed to make 1 L of a 1-M solution? Use details to support your answer.

200 g C₆H₁₂O₆

General Formulas and Concepts:

Chemistry - Solutions

Explanation:

Step 1: Define

1 M C₆H₁₂O₆

1 L of solution

Step 2: Identify Conversions

Molar Mass of C - 12.01 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol

Step 3: Find moles of solute

1 M C₆H₁₂O₆ = x mol C₆H₁₂O₆ / 1 L

x = 1 mol C₆H₁₂O₆

Step 4: Convert

= 180.18 g C₆H₁₂O₆

Step 5: Check

We are given 1 sig figs. Follow sig fig rules and round.

180.18 g C₆H₁₂O₆ ≈ 200 g C₆H₁₂O₆

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.