Calculate the number of sulfate ions in 41.65 g of aluminum sulfate.

The number of sulfate ions : 2.2 x 10²³

Further explanation

Reaction

Al₂(SO₄)₃⇒2Al³⁺+3SO₄²⁻

mol Al₂(SO₄)₃(MW=342,15 g/mol) :

mol of sulfate ions (SO₄²⁻)

1 mol = 6.02 x 10²³ particles (ions, molecules, atoms), so for 0.366 mol :

It’s b. mass i searched it up

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