What is the volume of 902.0 g of C₂H₄ gas at STP

Volume  = 722.1 L

Explanation:

Given data:

Mass of gas = 902.0 g

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Volume of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will calculate the number of moles of C₂H₄.

Number of moles = mass/molar mass

Number of moles = 902.0 g/ 28.05 g/mol

Number of moles = 32.2 mol

Volume of gas:

PV = nRT

1 atm ×V = 32.2 mol × 0.0821   atm.L/ mol.K  × 273.15 K

V = 722.1 atm.L/1 atm

V = 722.1 L

i think is conclusions.i think so