What mass of citric acid (molar mass = 192.14g/mol) would be needed to make 0.10 L of 5.00 M citric acid solution ?

Mass = 96.07 g

Explanation:

Given data:

Mass of citric acid = ?

Molar mass of citric acid = 192.14 g/mol

Volume of citric acid solution = 0.10 L

Molarity of solution = 5.00 M

Solution:

First of all we will calculate the number of moles from molarity formula. Then we will determine the mass from moles formula.

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

5.00 M = n/0.10 L

n = 5.00 mol/L× 0.10 L

n =0.5 mol

Mass of citric acid:

Number of moles = mass/molar mass

0.5 mol = mass/ 192.14 g/mol

Mass = 0.5 mol  × 192.14 g/mol

Mass = 96.07 g

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.