Determine the mass of CaCl2·2H2O(MW 147.02g/mole) to weigh out using a four-place analytical balance to prepare 100mL of a 0.1005M solution of Ca2+.

1.4776 g

Explanation:

First, let us determine the number of moles present in  100 mL of 0.1005 M solution of Ca2+.

mole = molarity x volume in Liter

mole of Ca2+ = 0.1005 x 0.1 = 0.01005

Also,

mole = mass/molar mass

mass of 0.01005 mole Ca2+ = mole x molar mass

                 = 0.01005 x 147.02 = 1.4776 g

Since 1 mole of Ca2+ is present is 1 mole of CaCl2·2H2O, 1.4776 g of CaCl2·2H2O would be weighed out in order to prepare 00mL of a 0.1005M solution of Ca2+.

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.